Library code snippets
Loading Huge Files
By Kym Manson, published on 12 Mar 2002
l is set to 2k, 2*1024. this is the buffer size, ie: how much to load in each go
strFile is the name of the file to open.
Dim l as long, sz as long
Dim FN As Integer
Dim strFile As String, c As String
FN = FreeFile
Open strFile For Binary Access Read As #FN
l = 2 * 1024: c = Space$(l) ' 2k Buffer Size, 2 * 1024
sz = LOF(FN)
If sz / l Then
For d = 1 To sz / l
Get #FN, , c
MsgBox c
Next
End If
' load remainder of file, if filesize is not exactly divisable by l (2k)
l = sz Mod l
If l Then
c = Space$(l)
Get #FN, , c
MsgBox c
End If
Close #FN
The data loaded is returned in variable
c. Do whatever you like with it..
Till the Roof comes off Till the Lights go out Till my Legs give out Can't shut my mouth I will not fall, my Wisdoms all.
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I'll correct the code.
strC = strSpace(FN) should be strC=Space$(l)
in fact strC is wrong, because it ain`t declared as a String, which means its defaulted to variant, so it should be varC
Heres the original code..
File$ is the filename or variable holding the filename
Data is returned in Variable c$ (String) ($ = String DataType)
Dim l as long, sz as long
Open File$ For Binary Access Read As #1
l = 1024: c$ = Space$(l)
sz = LOF(1)
If sz / l Then
For d = 1 To sz / l
Get #1, , c$
MsgBox c$ ' Do whatever with the inputted data
Next
End If
' Load remainder of file, if FileSize (sz) is not exactly divisable by l (2k, BufferSize)
l = sz Mod l
If l Then
c$ = Space$(l)
Get #1, , c$ ' Do whatever with the inputted data
MsgBox c$
End If
Close #1
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