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about array..

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  8 months ago

  by krishnareddyav

  krishnareddyav

  , India

  Joined 10 months ago

  how will i do this one: Create a program that will 1. allow user to input 5 numbers using array. 2. Determine if the list is UNIQUE or NOT UNIQUE NOTE: UNIQUE - if there are no similar elements in the list NOT-UNIQUE - if there are similar elements in the list EXAMPLE: 1 2 3 4 4 It's NOT UNIQUE! please help me..

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• • Reply

  8 months ago

  by Uncle

  Uncle

  England, United Kingdom

  Joined 6 years ago

   

  Here's some pseudocode for one method of solving your problem:

  Create the array.

  Get the five inputs and store them in the array.

  Sort the array into ascending order using your favourite sort algorithm.

  Create a Boolean and set it to False.

  Loop through the five variables; if one is the same as the next one, set the Boolean to True.

  If the Boolean is True, the list is Not Unique, otherwise the list is Unique.

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  8 months ago

  by sithkong

  Sith Kong

  Charlotte, United States

  Joined 9 months ago

   Hi

  Here's a console program that solves the problem.

  Input is evaluated to check if the user has typed in an integers and it it's unique.

  The unique check is done by comparing the new integers with the previous accepted integers.

  /* Input5uniquenumbers.java
   * Created on 22. marts 2008, 23:56
   */
  import java.io.*;
  public class Input5uniquenumbers {  
      public static void main(String[] args) {
         
          int numberOfInputs = 5;
          System.out.println( "\nPlease type in " + numberOfInputs + " integers: " );
         
          InputStreamReader isr = new InputStreamReader( System.in );
          BufferedReader stdin = new BufferedReader( isr );

          String rawInput;
          int inputAsInteger = -1;
          int[] goodInteger = new int[numberOfInputs +1];
          goodInteger[0] = -1;    // index 0 is ignored
         
          boolean inputOk;
          boolean isUnique;
          //
          for ( int intNum = 1; intNum <= numberOfInputs; intNum++) {
          
              inputOk = true;
              rawInput = null;
              System.out.print( "\n" + intNum + ". integer ..");
             
              try {
                   rawInput = stdin.readLine();
                   inputAsInteger = Integer.parseInt( rawInput.trim() );
              } catch (IOException ioError) {
                   inputOk = false;
                   System.err.println( ioError );
              } catch (NumberFormatException ioError ) {
                   inputOk = false;
                   System.err.println( "Not an integer" );
              }
             
              // Evaluation
              if ( inputOk )  {
                  // is the number unique ?
                  isUnique = true;
                  // compares the previous accepted integers with the new one
                  for(int ix = 1; ix < intNum; ix++) {
                      if ( goodInteger[ix] == inputAsInteger ) {
                          isUnique = false;
                          System.err.println( "Not unique" );
                      }
                  }
                  if ( isUnique ) {
                      goodInteger[intNum] = inputAsInteger;
                  } else {
                      intNum--;           // eliminate the for loops intNum++
                  }
              } else {
                  intNum--;
              }
         
          }//ends for loop
         
          System.out.print( "\nYou typed in the following unique integers: " + goodInteger[1]);
          for(int ix = 2; ix <= numberOfInputs; ix++) {
              System.out.print( ", " + goodInteger[ix]  );
          }
      }//ends main()
  }

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• • Reply

  7 months ago

  by krishnareddyav

  krishnareddyav

  , India

  Joined 10 months ago

  thanks for the help 

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• • Reply

  6 months ago

  by Mane

  Mane

  , South Africa

  Joined 8 months ago

  Hello everyone 

  Seems you have your problem solved. I came into the thread to see if I could help, but was beaten to the punch.

  Best of luck!! .... Les ..... data recovery software 

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