Number of days
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Hi,
I have this function:Public Function NewReleasesTime(ByVal Time As String) As Integer Select Case Time Case "One Week" Return 7 Case "Two Weeks" Return 14 Case "Three Weeks" Return 21 Case "One Month" Return 30 Case "Two Months" Return 60 Case "Three Months" Return 90 Case "One Year" Return 365 Case "Two Years" Return 730 Case "Three Years" Return 1095 End Select End FunctionThere is no method in VB 2005 that when is got the word “One Week” it return the number 7 (that means seven days)? -
Uf I guess it is not necessary to process data like this. But I don't see kontext in which this crappy function should be needed :)
Anyway, I think (hope), that there is no function like this :)... but if you prefer that way, you should make it more efficient... for example you can make one string like this with fixed atom length, where atom is part of that string containing e.g. "Three Years" and rest of atom is filled by some special char
like this:
function GRT(name as string) as int
TMP = "$monday---$tuesday---$wensday---$friday----etc"
and you only once run Instr(TMP,name)
-- you will get e.g. 0 for monday, 10 for tuesday, 20 for ...
you divide that with 10 - and you get PTR
and you have array DayInWeek of int {1,2,3,4,5,6,0}
where PTR applied on diw array will return you day in week...
it is quicker I quess - only one string search, not n string comparings.
Also Array.IndexOf(ArrayOfStrings,Needle) should be faster than select case on strings.
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I don't know of any function to do what your asking but I had an idea that will work. The thing you need to solve is really just converting a word to it's value. For instance if we can covert ten to 10 then we could figure out the number of days by multiplying by the appropriate value. 10 weeks we multiply by 7; 10 months we multiply by 30.
I tinkered with creating a function that could convert a word to it's actual numeric value. So for instance "ten thousand seven hundred and forty-one" would be appropriatly converted to 10741. I'll post the code below. Hopefully it's self explanitory but basically you pass in a string that represents a number like the one I just mentioned and it returns the real value. Now all you need to do is create another function (which should be pretty easy) that converts the words "month" "week" etc. to the appropriate multiplier. You can the parse your string of "three weeks" pass "three" to my function and multiply the result by the result of your function to be created. Make sense? This should allow you to create a very robust function without limits. Hope this helped. The function should work but if you have any problems let me know.
'I didn't handle overflow errors so any number over the max integer 'will throw an error. This should normally be dealt with. Private Function ConvertWordToNumber(ByVal num As String) As Integer Dim value As Integer = 0 'Convert to all lower case and remove hyphens and spaces. 'I think that's all that needs to be done here. num = num.ToLower num = num.Replace(" "c, "") num = num.Replace("-"c, "") Do While num.Length > 0 Dim length = num.Length If num.StartsWith("twenty") Then value += 20 num = num.Remove(0, 6) ElseIf num.StartsWith("thirty") Then value += 30 num = num.Remove(0, 6) ElseIf num.StartsWith("forty") Then value += 40 num = num.Remove(0, 5) ElseIf num.StartsWith("fifty") Then value += 50 num = num.Remove(0, 5) ElseIf num.StartsWith("sixty") Then value += 60 num = num.Remove(0, 5) ElseIf num.StartsWith("seventy") Then value += 70 num = num.Remove(0, 7) ElseIf num.StartsWith("eighty") Then value += 80 num = num.Remove(0, 6) ElseIf num.StartsWith("nintey") Then value += 90 num = num.Remove(0, 6) ElseIf num.StartsWith("ten") Then value += 10 num = num.Remove(0, 3) ElseIf num.StartsWith("eleven") Then value += 11 num = num.Remove(0, 6) ElseIf num.StartsWith("twelve") Then value += 12 num = num.Remove(0, 6) ElseIf num.StartsWith("thirteen") Then value += 13 num = num.Remove(0, 8) ElseIf num.StartsWith("fourteen") Then value += 14 num = num.Remove(0, 8) ElseIf num.StartsWith("fifteen") Then value += 15 num = num.Remove(0, 7) ElseIf num.StartsWith("sixteen") Then value += 16 num = num.Remove(0, 7) ElseIf num.StartsWith("seventeen") Then value += 17 num = num.Remove(0, 9) ElseIf num.StartsWith("eighteen") Then value += 18 num = num.Remove(0, 8) ElseIf num.StartsWith("nineteen") Then value += 19 num = num.Remove(0, 8) ElseIf num.StartsWith("zero") Then num = num.Remove(0, 4) ElseIf num.StartsWith("one") Then value += 1 num = num.Remove(0, 3) ElseIf num.StartsWith("two") Then value += 2 num = num.Remove(0, 3) ElseIf num.StartsWith("three") Then value += 3 num = num.Remove(0, 5) ElseIf num.StartsWith("four") Then value += 4 num = num.Remove(0, 4) ElseIf num.StartsWith("five") Then value += 5 num = num.Remove(0, 5) ElseIf num.StartsWith("six") Then value += 6 num = num.Remove(0, 3) ElseIf num.StartsWith("seven") Then value += 7 num = num.Remove(0, 5) ElseIf num.StartsWith("eight") Then value += 8 num = num.Remove(0, 5) ElseIf num.StartsWith("nine") Then value += 9 num = num.Remove(0, 4) ElseIf num.StartsWith("hundred") Then value *= 100 num = num.Remove(0, 7) ElseIf num.StartsWith("thousand") Then value *= 1000 num = num.Remove(0, 8) Return value + ConvertWordToNumber(num) ElseIf num.StartsWith("million") Then value *= 1000000 num = num.Remove(0, 7) Return value + ConvertWordToNumber(num) ElseIf num.StartsWith("billion") Then value *= 1000000000 num = num.Remove(0, 7) Return value + ConvertWordToNumber(num) ElseIf num.StartsWith("and") Then num = num.Remove(0, 3) End If 'Length of our variable didn't change so we know 'nothing was stripped from it. 'This would result in an infinite loop so we need to exit 'An error should probably be raised. If length = num.Length Then Exit Do Loop Return value End Function -
Hi TwoFaced,
I will let you know how this function is working and the MyTextBox class two. Thanks a lot.
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Ya, sorry for my misunderstand - twofaceds func does give sense to question also solution.
:)
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