Error message

• • Reply

  13 years ago

  by bigCountry

  John Wiley

  , United States

  Joined 13 years ago

  Hi I am having problems with my code.
  It is given me an error message stating "cannot find symbol variable
  NotCont"where the arrow is.
  Can some one help me with this please.
  Thanks ^_^  

  import java.util.Scanner;
  public class IntegerSetTest
  {
          public static void main(String[] args)
          {
                  Scanner input = new Scanner (System.in);
  

                  System.out.println("Welcome to the Integer Set\n");
  

          System.out.println("This program is going to find the union " +
                  " or intersection of any two sets you enter" +
                  "\nPlease enter the number of sets: ");
          int  intArray[] = new int[100];
                  int value;
          try
          {
                  do
                  {
                          int i;
  

                          value = input.nextInt();
                          intArray[i]=value;
                          System.out.println("Enter -1 to end: ");
                          int NotCont = input.nextInt();
                          i++;
  --->                 }while(NotCont != -1);
  

                  for(int i=0; i<intArray.length;i++)
                  {
                          System.out.println(intArray[i]);
                  }
          }
          catch(NumberFormatException ex)
          {
          }
      }
  }

  </code>

  Report abuse
• • Reply

  13 years ago

  by drogonevets

  steve coleman-williams

  Aberystwyth-Wales, United Kingdom

  Joined 16 years ago

  you have

  do

  {

  int i;

  value = input.nextInt();

  intArray[i]=value;

  System.out.println("Enter -1 to end: ");

  int NotCont = input.nextInt();

  i++;

  } while(NotCont != -1);

  you need

  int NotCont = 0;

  do

  {

  int i;

  value = input.nextInt();

  intArray[i]=value;

  System.out.println("Enter -1 to end: ");

  NotCont = input.nextInt(); i++;

  } while(NotCont != -1);

  you cannot initialise a variable within a loop as there is a chance (usually slim but none the less) tjhat the program wont go into that loop and therefore wont be created. also you might have the same problem with your try catch so my want to put it out of there too
  Report abuse
• • Reply

  13 years ago

  by bigCountry

  John Wiley

  , United States

  Joined 13 years ago

  Ok, thanks

  Report abuse