Use .ini as a resource

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  15 years ago

  by gsg

  Gouri

  , India

  Joined 15 years ago

  Hi All,

  i am using  an .INI file in my application. but i want to use it as a resource, say embedded in some dll, rather to make it viewable physically.

  how can i make it possible?

  plz help...

  thanks for your time in advance...

  -Gouri

   

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  15 years ago

  by gsg

  Gouri

  , India

  Joined 15 years ago

  any ideas...plzz...

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  15 years ago

  by alpha7s2ar

  alpha7s2ar

  Yorkshire, United Kingdom

  Joined 15 years ago

  Using an .ini I'm not quite sure by what u mean by an embedding an .dll but there are two API calls which lets you save and get program information from an .ini what they are I can't remeber and the site I've been using for API is at  home right now.... try query the msdn libary about it.

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  15 years ago

  by gsg

  Gouri

  , India

  Joined 15 years ago

  Hi! thanks for your response.

  let me elaborate my problem:

  i am using .INI files as a database file for my project which at present i have kept on the App path. but i dont want that file to be visible by anyone so, i wish to hide it. i think it can be embedded into a .dll so as to access it from there.

  but i dont know how to implement it. is there any other way to implement this task? any ideas??

   

   

   

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  15 years ago

  by alpha7s2ar

  alpha7s2ar

  Yorkshire, United Kingdom

  Joined 15 years ago

  I don't think so .ini files arn't mean't to be used as a database there the old equivilent to the windows registry, used to store the program settings (route path) etc. look at the windows registry for an example.

  a better way to do a flat-file database and not to not let anyone see the contents is to use a .dat file with the file system commands there a lot easier than ado or dao langerages given that its a flat file to create a record create a new type eg.:

  Type NameRecord
  name as string * 15
   end Type
  
  

  Public sub Writetodatabase(byval strname as string)

  Dim Person as NameRecord
  Dim Intfile as Integer
  

  fido.name = strname

  Intfile = freefile() 'sets Intfile equal to the next free filenumber

  Open filename.dat for random Len=Len(nameRecord) as Intfile 'Len Is the size of the record
  Put Intfile, [record number], fido 'record number is optional
  close Intfile
  
  

  End sub

  and to retive a record

  Public Function RetiveRecord as nameRecord

  Dim Intfile as Integer
  Dim Person as Record
  

  Intfile = freefile()
  Open filename.dat for random Len=Len(nameRecord) as Intfile
  Get Intfile,[record number], Person
  RetiveRecord = Person
  
  
  

  End sub

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